🚀 Can equals(Object that) Be Implemented as return this.hashCode() == that.hashCode();?
No, 2 objects, having same hashcode (collissions) maybe not equal acually.
No, this is an incorrect implementation of equals().
It violates the contract of equals() and leads to incorrect behavior in hash-based collections.
1️⃣ Why Is This Implementation Wrong?
❌ Incorrect equals() Implementation
@Override
public boolean equals(Object that) {
return this.hashCode() == that.hashCode(); // ❌ Wrong!
}
📌 What’s Wrong?
- Two different objects can have the same
hashCode()(hash collisions). - Equal hash codes (
hashCode() == hashCode()) do not guarantee object equality. - This breaks the
equals()contract, causing incorrect behavior in collections likeHashSetandHashMap.
2️⃣ equals() Contract vs. hashCode()
📜 Java’s equals() Contract
For an object x:
- Reflexivity:
x.equals(x) == true - Symmetry: If
x.equals(y), theny.equals(x) - Transitivity: If
x.equals(y)andy.equals(z), thenx.equals(z) - Consistency:
x.equals(y)should always return the same result ifxandydon’t change nullHandling:x.equals(null) == false
🚨 What Happens If equals() Uses hashCode()?
- Hash collisions cause
equals()to returntruefor different objects. - Objects with the same
hashCode()but different content would be incorrectly treated as equal. - Violates symmetry and transitivity.
3️⃣ Example: Hash Collisions Break equals()
class Person {
private String name;
public Person(String name) {
this.name = name;
}
@Override
public boolean equals(Object obj) {
return this.hashCode() == obj.hashCode(); // ❌ Wrong!
}
@Override
public int hashCode() {
return 42; // ❌ All objects have the same hash code!
}
}
public class Main {
public static void main(String[] args) {
Person p1 = new Person("Alice");
Person p2 = new Person("Bob");
System.out.println(p1.equals(p2)); // ❌ true (Incorrect! Different people should not be equal)
}
}
📌 What Went Wrong?
- Since both
p1andp2return42forhashCode(),equals()incorrectly returnstrue. p1andp2should not be equal, but they are because of the flawed implementation.
4️⃣ Correct Implementation of equals()
✅ Fixed equals()
import java.util.Objects;
class Person {
private String name;
public Person(String name) {
this.name = name;
}
@Override
public boolean equals(Object obj) {
if (this == obj) return true; // ✅ Reflexivity
if (obj == null || getClass() != obj.getClass()) return false;
Person person = (Person) obj;
return Objects.equals(name, person.name); // ✅ Compare actual content
}
@Override
public int hashCode() {
return Objects.hash(name); // ✅ Uses name to generate hash
}
}
📌 Now equals() correctly compares content, not just hash codes.
5️⃣ Key Differences: equals() vs. hashCode()
| Method | Purpose | Can Two Objects Have the Same Value? |
|---|---|---|
equals() | Checks logical equality (content comparison). | ❌ No, if equals() returns true, objects must be logically equal. |
hashCode() | Generates an integer for efficient storage in hash-based collections. | ✅ Yes, different objects can have the same hash code (hash collisions). |
🚀 Correct Relationship
- If
equals(x, y) == true, thenhashCode(x) == hashCode(y). - If
hashCode(x) == hashCode(y),equals(x, y)may or may not be true.
📌 Summary: Why equals() Should Not Rely on hashCode()
| Issue | Why It Fails |
|---|---|
| Hash Collisions | Different objects can have the same hash code. |
Violates equals() Contract | Objects that should be different might be treated as equal. |
Breaks HashSet and HashMap | Causes incorrect behavior in collections. |
✅ Best Practices
✔ equals() should compare actual fields, not hash codes.
✔ Override both equals() and hashCode() correctly.
✔ Use Objects.equals() for null-safe comparison.
By following these rules, your Java objects will work correctly and efficiently in collections! 🚀